Can someone answer this physics problem from my homework? I have absolutley no idea where to start?

Starting from when the speeder pes the cop, for the speeder, s=30t where s=distance from where he ped the cop. For the cop, s=1/2 x 2.44 x t^2 = 1.22 x t^2. The speeder is overtaken when 1.22t^2=30t, so 1.22t=30, so t=30/1.22=24.59 secs., and in this time the speeder has travelled 30x24.59=737.7 metres.